It’s not hard to solve our cubic equation and find the third point of intersection to be \left (-\frac {7} {4},-\frac {13} {8}\right). As with the circle, this argument generalizes: If a line ...

Higher Rectilinear shapes Point of intersection Find the gradient, equations and intersections of medians, altitudes and perpendicular bisectors using our knowledge of the mid-point as well as ...